Wie konvertiert man 9 = (- 2x + y) ^ 2-5y + 3x in polare Form?

Antworten:

# 9 = 4r ^ 2cos ^ 2 (theta) -4r ^ 2sinthetacostheta + r ^ 2sin ^ 2 (theta) -5rsintheta + 3rcostheta = r (sintheta (r (sintheta-4costheta) -5) + costheta (4rcostheta + 3)) #

Erläuterung:

# x = rcostheta #

# y = rsintheta #

# 9 = (- 2 (rcostheta) + rsintheta) ^ 2-5rsintheta + 3rcostheta #

# 9 = 4r ^ 2cos ^ 2 (theta) -4r ^ 2sinthetacostheta + r ^ 2sin ^ 2 (theta) -5rsintheta + 3rcostheta #

# 9 = r (sintheta (r (sintheta-4costheta) -5) + costheta (4rcostheta + 3)) #